4x^2+19xy+12y^2=0

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Solution for 4x^2+19xy+12y^2=0 equation:


Simplifying
4x2 + 19xy + 12y2 = 0

Reorder the terms:
19xy + 4x2 + 12y2 = 0

Solving
19xy + 4x2 + 12y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4x + 3y)(x + 4y) = 0

Subproblem 1

Set the factor '(4x + 3y)' equal to zero and attempt to solve: Simplifying 4x + 3y = 0 Solving 4x + 3y = 0 Move all terms containing x to the left, all other terms to the right. Add '-3y' to each side of the equation. 4x + 3y + -3y = 0 + -3y Combine like terms: 3y + -3y = 0 4x + 0 = 0 + -3y 4x = 0 + -3y Remove the zero: 4x = -3y Divide each side by '4'. x = -0.75y Simplifying x = -0.75y

Subproblem 2

Set the factor '(x + 4y)' equal to zero and attempt to solve: Simplifying x + 4y = 0 Solving x + 4y = 0 Move all terms containing x to the left, all other terms to the right. Add '-4y' to each side of the equation. x + 4y + -4y = 0 + -4y Combine like terms: 4y + -4y = 0 x + 0 = 0 + -4y x = 0 + -4y Remove the zero: x = -4y Simplifying x = -4y

Solution

x = {-0.75y, -4y}

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